JAKA0EBFRST IFSC Code
Jammu and Kashmir Bank EBU FOREST BLOCK KANGAN branch — Ganderbal, Jammu And Kashmir. Use this IFSC code for NEFT, RTGS and IMPS fund transfers.
| Bank | Jammu and Kashmir Bank |
|---|---|
| Branch | EBU FOREST BLOCK KANGAN |
| IFSC Code | JAKA0EBFRST |
| MICR Code | |
| Address | VILLAGE FOREST BLOCK POST OFFICE SONAMARG TEHSIL GUND DISTRICT GANDERBAL PIN 191203 LANDMARK MAIN MARKET SONAMARG |
| Contact | +919015607007 |
| City | Ganderbal |
| District | Ganderbal |
| State | Jammu And Kashmir |
How to Use JAKA0EBFRST for Fund Transfer
- Log in to your net banking or mobile banking app and go to the fund transfer section.
- Add a new beneficiary with the account holder's name and account number.
- Enter JAKA0EBFRST as the IFSC code for Jammu and Kashmir Bank EBU FOREST BLOCK KANGAN branch.
- Choose NEFT, RTGS or IMPS, enter the amount and confirm the transfer.
Other Jammu and Kashmir Bank Branches in Ganderbal
JAKA0BAKURABAKURA GANDERBALJAKA0BATWINBATWINA GANDERBALJAKA0CHATGBCHATTERGULJAKA0CHDUNACHUNDUNAJAKA0DABGNBDABJAKA0DORSUMDORSUMA MANIGAMJAKA0DUDRHMDUDERHAMAJAKA0EBHARIEBU HARI GANIWANJAKA0EBSHALEBU SHALLABUGHJAKA0EBYOUNEBU YOUNGORAJAKA0ECNBALNAGBALJAKA0ESANIKSAINIK SCHOOL MANASBALJAKA0EWAKURWAKURAJAKA0GANDERGANDERBALJAKA0GOUNDHGUNDJAKA0KANGANKANGANJAKA0KULANGKULLANJAKA0MANGAMMANIGAMJAKA0NUNNARNUNNERJAKA0PIRPURPEERPUR CHOWK
Frequently Asked Questions
What is JAKA0EBFRST IFSC code?
JAKA0EBFRST is the IFSC code of Jammu and Kashmir Bank EBU FOREST BLOCK KANGAN branch in Ganderbal, Jammu And Kashmir.
Which bank is JAKA0EBFRST?
JAKA0EBFRST belongs to Jammu and Kashmir Bank. It is the EBU FOREST BLOCK KANGAN branch located in Ganderbal, Jammu And Kashmir.
How to use JAKA0EBFRST for NEFT, RTGS and IMPS?
Enter JAKA0EBFRST as the IFSC code along with the beneficiary's account number and name when making NEFT, RTGS or IMPS transfers to this branch.
What is the MICR code of Jammu and Kashmir Bank EBU FOREST BLOCK KANGAN branch?
The MICR code of Jammu and Kashmir Bank EBU FOREST BLOCK KANGAN branch is .